4 条题解

  • 3
    @ 2024-5-31 16:08:30
    #include <cstring>
    #include <algorithm>
    using namespace std;
    int main()
    {
        int n;
        cin >> n;
        int ans = 0;
        int t1 = n / 100;
        int t2 = n /10%10;
        int t3 = n % 10;
        if(t3 != 0)
        {
            ans =t3 * 100 + t2 * 10 + t1;
        }
        else 
        {
            ans = t2 * 10 + t1;
        }
        cout << ans <<endl;
        
    }
    
    • 1
      @ 2025-8-19 9:23:50
      #include<bits/stdc++.h>
      using namespace std;
      int main(){
          int n;
          cin>>n;
          int t1=n%10;
          int t2=n/10%10;
          int t3=n/100;
          cout<<t1*100+t2*10+t3;
          return 0;
      }
      
      • 0
        @ 2026-8-22 11:50:33

        num1 = input() bai = int(num1[0]) shi = int(num1[1]) ge = int(num1[2]) print(ge100 + shi10 +bai)

        • 0
          @ 2025-10-4 13:50:36
          #include<stdio.h>
                int main()
              {
          	int n,m;
          	scanf("%d",&n);
          	if(n>=100&&n<=999){
          	
          	
          	m=n%10;
          	switch(m)
          	{
          	case 0:{
          	while(n!=0)
          	{
          	if(m!=0)printf("%d",m);
          	n=n/10;
          	m=n%10;}
          	}break;
          	default:{
          	while(n!=0)
          	{
          	printf("%d",n%10);
          	n=n/10;}
          	
          	}break;
          		
              }
              }
          	return 0;
              }
          
          • 1

          信息

          ID
          198
          时间
          1000ms
          内存
          128MiB
          难度
          1
          标签
          递交数
          1382
          已通过
          385
          上传者